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How To Find Lcm Of Algebraic Fractions

LCM of Algebraic Expressions

To calculate the LCM (Lowest Common Multiple) of the given algebraic expressions, we should convert the algebraic expressions into their simplest factors. And, so the product of their common factors and the remaining factors will give the LCM of the given algebraic expressions.

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LCM = Common factors × Remaining factors

For example: 10two + 5x + half-dozen and x2 + 3x + 2 are two algenraic expressions. x2 + 5x + 6 = (x + 2)(x + 3) and x2 + 3x + two = (x + 1)(x+2) are their simplest factors. And, (x + ane)(x + 2)(x + iii) is the production of their common and remaining factors. And so, LCM of 10two + 5x + six and 10two + 3x + 2 is (x + 1)(x + 2)(x + 3).

LCM in Venn diagram

While finding LCM, we should use the following steps:

Steps :

i. Factorize the given algebraic expressions.

two. Take out the common factors and and so the remaining factors.

3. The production of mutual and remaining factors will requite the required LCM.

The concept of LCM will be more clear from the following worked-out examples.

Worked Out Examples

Example ane: Find the LCM of 3x2yz, 4y2z and 5xz2

Solution:

Here,

onest expression = 3x2yz = 3 × 10 × x × y × z

2nd expression = 4y2z = 2 × 2 × y × y × z

threerd expression = 5xz2 = 5 × x × z × z

LCM = three × 2 × 2 × 5 × x × x × y × y × z × z

= 60x2ytwoz2

Example 2: Find the LCM of m4 – 4mii and 3m2 + 6m

Solution:

Here,

onest expression = miv – 4mii

= m2(m2 – 4)

= grand2(m2 – 22)

= m × m(m + two)(grand – two)

2nd expression = 3m2 + 6m

= 3m(m + ii)

LCM = 3m × m(m + 2)(yard – two)

= 3m2(g + 2)(m – 2)

Example 3: Detect the LCM of a2 – 3a + two, a4 + a3 – 6a2 and a3 + 2a2 – 3a

Solution:

Here,

1st expression = aii – 3a + 2

= a2 – (2 + i)a + 2

= a2 – 2a – a + ii

= a(a – 2) – 1(a – 2)

= (a – 2)(a – 1)

2nd expression = aiv + a3 – 6a2

= a2(a2 + a – half dozen)

= a2{a2 + (3 – 2)a – 6}

= aii(a2 + 3a – 2a – 6)

= aii{a(a + three) – 2(a + iii)}

= a × a(a + three)(a – ii)

3rd expression = a3 + 2a2 – 3a

= a(a2 + 2a – iii)

= a{a2 + (3 – 1)a – 3}

= a(atwo + 3a – a – 3)

= a{a(a + iii) – ane(a + 3)}

= a(a + 3)(a – 1)

LCM = a × a(a – one)(a – 2)(a + 3)

= aii(a – 1)(a – 2)(a + 3)

Example 4: Observe the LCM of ten2 – 5x + 6, x2 + 4x – 12 and x2 – 2x

Solution:

Here,

anest expression = x2 – 5x + 6

= x2 – (3 + 2)x + 6

= x2 – 3x – 2x + 6

= x(ten – 3) – 2(x – 3)

= (x – 3)(ten – ii)

2nd expression = x2 + 4x – 12

= xii + (vi – 2)x – 12

= x2 + 6x – 2x - 12

= 10(ten + 6) – ii(x + 6)

= (x + 6)(x – 2)

threerd expression = tenii – 2x

= 10(x – 2)

LCM = x(x – two)(ten – 3)(x + half-dozen)

Example 5: Find the LCM of a2 – b2 – 2bc – ctwo, b2 – cii – 2ca – a2 and c2 – a2 – 2ab – b2

Solution:

Here,

anest expression = a2 – b2 – 2bc – c2

= atwo – (b2 + 2bc + ctwo)

= aii – (b + c)two

= (a + b + c)(a – b – c)

twond expression = btwo – cii – 2ca – a2

= b2 – (c2 + 2ca + a2)

= btwo – (c + a)2

= (b + c + a)(b – c – a)

= (a + b + c)(b – c – a)

threerd expression = cii – atwo – 2ab – btwo

= c2 – (a2 + 2ab + bii)

= c2 – (a + b)2

= (c + a + b)(c – a – b)

= (a + b + c)(c – a – b)

LCM = (a + b + c)(a – b – c)(b – c – a)(c – a – b)

Example 6: Find the LCM of a3 – 2atwob + 2ab2 – biii, afour + b4 + a2btwo and 4aivb + 4ab4

Solution:

Here,

1st expression = a3 – 2aiib + 2abtwo – b3

= a3 – b3 – 2a2b + 2ab2

= (a – b)(a2 + ab + bii) – 2ab(a – b)

= (a – b)(atwo + ab + b2 – 2ab)

= (a – b)(a2 – ab + b2)

2nd expression = afour + b4 + a2b2

= (aii)2 + 2a2b2 + (btwo)2 – a2bii

= (atwo + btwo)2 –(ab)two

= (a2 + b2 + ab)(a2 + b2 – ab)

= (a2 + ab + b2)(aii – ab + b2)

iiird expression = 4a4b + 4ab4

= 4ab(a3 + b3)

= 4ab(a + b)(a2 – ab + b2)

LCM = 4ab(a + b)(a – b)(atwo + ab + btwo)(a2 – ab + btwo)

Example 7: Find the LCM of a2 – 18a – xix + 20b – b2, a2 + a – bii + b and 4atwo – 4btwo + 8b - iv

Solution:

Here,

anest expression = a2 – 2.a.9 + nine2 – 100 + 20b – b2

= (a – ix)ii – (10two – ii.10.b + b2)

= (a – 9)2 – (ten – b)2

= {(a – 9) + (10 – b)}{(a – 9) – (x – b)}

= (a – nine + ten – b)(a – 9 – 10 + b)

= (a – b + ane)(a + b – 19)

twond expression = a2 + a – btwo + b

= aii – btwo + a + b

= (a + b)(a – b) + 1(a + b)

= (a + b)(a – b + i)

iiird expression = 4a2 – 4b2 + 8b - 4

= 4(a2 – b2 + 2b – 1)

= iv{a2 – (btwo – 2b + 1)}

= 4{a2 – (b – 1)2}

= 4(a + b – ane)(a – b + 1)

LCM = 4(a + b)(a + b – ane)(a – b + 1)(a + b – xix)

Example eight: Find the LCM of 1 + 4a + 4a2 – 16a4, 1 + 2a – 8a3 – 16a4 and 1 – 8aiii

Solution:

Here,

1st expression = 1 + 4a + 4a2 – 16afour

= 1two + 2.1.2a + (2a)2 – (4a2)two

= (1 + 2a)2 – (4aii)two

= (1 + 2a + 4atwo)(one + 2a – 4a2)

twond expression = 1 + 2a – 8a3 – 16a4

= 1(i + 2a) – 8a3(ane + 2a)

= (1 + 2a)(1 – 8a3)

= (one + 2a){13 – (2a)3}

= (1 + 2a)(1 – 2a)(1 + 2a + 4a2)

3rd expression = 1 – 8a3

= 13 – (2a)3

= (1 – 2a)(ane + 2a + 4a2)

LCM = (1 + 2a)(1 – 2a)(1 + 2a + 4a2)(1 + 2a – 4aii)

If you have whatever question or problems regarding the LCM of algebraic expressions, you can ask hither, in the comment section below.

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How To Find Lcm Of Algebraic Fractions,

Source: https://www.10mathproblems.com/2020/06/lcm-of-algebraic-expressions.html

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